Return unique items using VBA in Microsoft Excel

In this article, we will create a macro to extract unique values from the defined range.

Raw data for this example consists of duplicate entries of country names in the range A7:A21.

ArrowMain

We have created “FindUniqueValues” macro to extract unique values from the defined range. This macro can be run by clicking the “Submit” button. Before clicking the “Submit” button, we have to specify the address of the range which contains duplicate data in the cell H9 and address of the destination where output should appear.

ArrowOutput

 

Logic explanation

“FindUniqueValues” macro takes two range objects as input parameters. First parameter defines the range which contains the duplicate data and second parameter defines the position of the starting cell which will contain the output. This macro cannot be called directly as we have to specify the parameters, so we have created second macro “MacroRunning” to call the macro.

“MacroRunning” macro calls the “FindUniqueValues” macro with the parameter input by the user.

Code explanation

SourceRange.AdvancedFilter Action:=xlFilterCopy, _

CopyToRange:=TargetCell, Unique:=True

AdvancedFilter method of Range object is used to filter or copy data from the range based on a certain criteria. To copy only the unique values, we have to set Unique parameter of AdvancedFilter to True.

 

Please follow below for the code


Option Explicit

Sub FindUniqueValues(SourceRange As Range, TargetCell As Range)

'Using advance filter for extacting unique items in the source range
SourceRange.AdvancedFilter Action:=xlFilterCopy, _
        CopyToRange:=TargetCell, Unique:=True
        
End Sub


Sub MacroRunning()

'Calling FindUniqueValues macro
Call FindUniqueValues(Range(Range("H9").Value), Range(Range("H10").Value))

End Sub

 

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Users are saying about us...

  1. "SourceRange and TargetCell can be on different worksheets, e.g. like this:
    FindUniqueValues Worksheets(1).Range(""A2:A100""), Worksheets(2).Range(""C1"") "

  2. "There are many possibilities here. One solutions is the following:

    Sub ExampleMultipleRanges()
    ' returnes the unique items from A1:A10;C1:C10 to E1 and downwards
    Dim varArray As Variant
    varArray = ReturnUniqueItems(True, Range(""A1:A10""), Range(""C1:C10""))
    ArrayToRange varArray, Range(""E1"")
    Erase varArray
    End Sub

    Function ReturnUniqueItems(blnReturnItems As Boolean, ParamArray InputRange()) As Variant
    ' returns the unique items or the count of unique items from a single range or multiple ranges
    Dim c As Collection, i As Long, cl As Range, arrResult() As Variant
    ReturnUniqueItems = CVErr(xlErrNA)
    Set c = New Collection
    For i = LBound(InputRange) To UBound(InputRange)
    For Each cl In InputRange(i)
    If Len(cl.Text) > 0 Then
    On Error Resume Next
    c.Add cl.Value, cl.Text ' ignores duplicates
    On Error GoTo 0
    End If
    Next cl
    Set cl = Nothing
    Next i
    If blnReturnItems Then ' return each unique item
    If c.Count > 0 Then
    ReDim arrResult(0 To c.Count - 1)
    For i = 1 To c.Count
    arrResult(i - 1) = c(i)
    Next i
    End If
    'ReturnUniqueItems = arrResult ' return data as a single row
    ReturnUniqueItems = Application.Transpose(arrResult) ' return data as a single column
    ' the transpose function can handle up to 5461 items
    Erase arrResult
    Else ' return the count of unique items
    ReturnUniqueItems = c.Count
    End If
    Set c = Nothing
    End Function

    Sub ArrayToRange(InputArray As Variant, UpperLeftCell As Range)
    ' fills the content of InputArray into a cell range starting at UpperLeftCell
    Dim d As Long, r As Long, c As Long
    If UpperLeftCell Is Nothing Then Exit Sub
    If Not TypeName(InputArray) Like ""*()"" Then Exit Sub
    d = ArrayDimensionCount(InputArray)
    If d 2 Then Exit Sub
    Select Case d
    Case 1 ' 1-dimensional array
    r = UBound(InputArray, 1)
    c = 1
    Case 2 ' 2-dimensional array
    r = UBound(InputArray, 1)
    c = UBound(InputArray, 2)
    End Select
    UpperLeftCell.Resize(r, c).Formula = InputArray
    End Sub "

  3. "This function was missing from my previous post:

    Function ArrayDimensionCount(InputArray As Variant) As Long
    ' returns the number of dimensions of InputArray
    Dim i As Long, d As Long
    If Not TypeName(InputArray) Like ""*()"" Then Exit Function ' return 0
    On Error Resume Next
    i = 0
    Do
    i = i + 1
    d = UBound(InputArray, i)
    Loop Until Err 0
    Err = 0
    On Error GoTo 0
    ArrayDimensionCount = i - 1 ' return the dimension count
    End Function "

  4. "SourceRange and TargetCell can be on different worksheets, e.g. like this:
    FindUniqueValues Worksheets(1).Range(""A2:A100""), Worksheets(2).Range(""C1"") "

  5. "There are many possibilities here. One solutions is the following:

    Sub ExampleMultipleRanges()
    ' returnes the unique items from A1:A10;C1:C10 to E1 and downwards
    Dim varArray As Variant
    varArray = ReturnUniqueItems(True, Range(""A1:A10""), Range(""C1:C10""))
    ArrayToRange varArray, Range(""E1"")
    Erase varArray
    End Sub

    Function ReturnUniqueItems(blnReturnItems As Boolean, ParamArray InputRange()) As Variant
    ' returns the unique items or the count of unique items from a single range or multiple ranges
    Dim c As Collection, i As Long, cl As Range, arrResult() As Variant
    ReturnUniqueItems = CVErr(xlErrNA)
    Set c = New Collection
    For i = LBound(InputRange) To UBound(InputRange)
    For Each cl In InputRange(i)
    If Len(cl.Text) > 0 Then
    On Error Resume Next
    c.Add cl.Value, cl.Text ' ignores duplicates
    On Error GoTo 0
    End If
    Next cl
    Set cl = Nothing
    Next i
    If blnReturnItems Then ' return each unique item
    If c.Count > 0 Then
    ReDim arrResult(0 To c.Count - 1)
    For i = 1 To c.Count
    arrResult(i - 1) = c(i)
    Next i
    End If
    'ReturnUniqueItems = arrResult ' return data as a single row
    ReturnUniqueItems = Application.Transpose(arrResult) ' return data as a single column
    ' the transpose function can handle up to 5461 items
    Erase arrResult
    Else ' return the count of unique items
    ReturnUniqueItems = c.Count
    End If
    Set c = Nothing
    End Function

    Sub ArrayToRange(InputArray As Variant, UpperLeftCell As Range)
    ' fills the content of InputArray into a cell range starting at UpperLeftCell
    Dim d As Long, r As Long, c As Long
    If UpperLeftCell Is Nothing Then Exit Sub
    If Not TypeName(InputArray) Like ""*()"" Then Exit Sub
    d = ArrayDimensionCount(InputArray)
    If d 2 Then Exit Sub
    Select Case d
    Case 1 ' 1-dimensional array
    r = UBound(InputArray, 1)
    c = 1
    Case 2 ' 2-dimensional array
    r = UBound(InputArray, 1)
    c = UBound(InputArray, 2)
    End Select
    UpperLeftCell.Resize(r, c).Formula = InputArray
    End Sub "

  6. "This function was missing from my previous post:

    Function ArrayDimensionCount(InputArray As Variant) As Long
    ' returns the number of dimensions of InputArray
    Dim i As Long, d As Long
    If Not TypeName(InputArray) Like ""*()"" Then Exit Function ' return 0
    On Error Resume Next
    i = 0
    Do
    i = i + 1
    d = UBound(InputArray, i)
    Loop Until Err 0
    Err = 0
    On Error GoTo 0
    ArrayDimensionCount = i - 1 ' return the dimension count
    End Function "

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